TEST 12: The geometry of the circle

MQ5 home    Test 11    1995 final


MQ5 TEST 12A (answers below)                                                                            Mr. Gary Jaye

INSTRUCTIONS:  1. Label all graphs and axes.
                                 2. Express all answers in simplest form and SHOW ALL WORK.

In 1 - 7, FILL IN the answers.                                         [2 each]

1. ry-axis(u,w)= 
 
2. ry=x(u,w)= 
 
3. rx-axis(u,w)= 
 
4. rx=7(3,8)= 
 
5. T6,3(-4,8)= 
 
6. If rk(-5,6) = (-5, -2), the     equation of k is: 
 
7. If Ta,b maps the graph of x2 + y2 = 49 onto the graph of
    (x - 4)2 + (y + 3)2 = 49,   a =??, b = ?? 

  SHOW WORK

8. Given chords AB and CD intersect at E, AE = x + 4, EB = 2x, CE = 3, ED = 3x + 5; Find AE.           [6]
 
9. Secants PAB and PCD are drawn from external point P, PA = 5, PB = 8, CD = 6; Find PC.               [5]
 

 
In 10 - 13, solve for 0° £ q < 360°


10. 2sinq = cscq                                                           [10]
 
 


11. cscq = -secq                                                          [10]
 
 
 


12. cot2q - cscq - 1 = 0                                               [15]
 
 


13. 2cosqsin = -cosq                                                    [10]
 
 
 


14. Solve over 0° £ q < 360° to the nearest MINUTE: 5cos2q + 7cosq + 2 = 0                               [15]
 
 
 


15. Segment PD is tangent to circle O at D, PAC is a secant, chords BD and AC intersect at E, chord AD is drawn, m(arc BC) = m(arc CA), m(arc BC) is twice m(arc AB), and
m<DAC = 48. Find:                                    [3 each]
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a. m(arc AB)  d. m<CED
b. m(arc AD)  e. m<ADP

c. m<CPD

 


ANSWERS: 1. (-u, w)  2. (w, u)   3. (u, -w)  4. (11, 8)  5. (2, 11)   6. y = 2  7. T4,-3   8. {AE = 3 + 4 = 7} 
9. {PC = 4} 10. (45°, 135°, 225°, 315°}  11. {135°, 315°}   12. {30°, 150°, 270°} 13. {90°, 210°, 270°,330°}
14. {113° 35', 180°, 246° 35'}  15a. 72°  15b. 48°  15c. 24°  15d. 84°  15e. 24°

MQ5 home    Test 11    1995 final